Call permission_is_exempt() to check for exempt permissions

This commit is contained in:
Jeremy Stretch 2020-06-01 13:17:59 -04:00
parent 3a9512f086
commit b6c38ceb73

View File

@ -6,14 +6,14 @@ from django.contrib.auth.models import Group
from django.db.models import Q
from users.models import ObjectPermission
from utilities.permissions import resolve_permission
from utilities.permissions import permission_is_exempt, resolve_permission
class ObjectPermissionBackend(ModelBackend):
def get_all_permissions(self, user_obj, obj=None):
if not user_obj.is_active or user_obj.is_anonymous:
return set()
return dict()
if not hasattr(user_obj, '_object_perm_cache'):
user_obj._object_perm_cache = self.get_object_permissions(user_obj)
return user_obj._object_perm_cache
@ -49,16 +49,9 @@ class ObjectPermissionBackend(ModelBackend):
if user_obj.is_active and user_obj.is_superuser:
return True
# If this is a view permission, check whether the model has been exempted from enforcement
if action == 'view':
if (
# All models are exempt from view permission enforcement
'*' in settings.EXEMPT_VIEW_PERMISSIONS
) or (
# This specific model is exempt from view permission enforcement
'{}.{}'.format(app_label, model_name) in settings.EXEMPT_VIEW_PERMISSIONS
):
return True
# Permission is exempt from enforcement (i.e. listed in EXEMPT_VIEW_PERMISSIONS)
if permission_is_exempt(perm):
return True
# Handle inactive/anonymous users
if not user_obj.is_active or user_obj.is_anonymous: