Fixes #20759: Group object types by app in permission form (#20931)

* Fixes #20759: Group object types by app in permission form

Modified the ObjectPermissionForm to use optgroups for organizing
object types by application. This shortens the display names (e.g.,
"permission" instead of "Authentication and Authorization | permission")
while maintaining clear organization through visual grouping.

Changes:
- Updated get_object_types_choices() to return nested optgroup structure
- Enhanced AvailableOptions and SelectedOptions widgets to handle optgroups
- Modified TypeScript moveOptions to preserve optgroup structure
- Added hover text showing full model names
- Styled optgroups with bold, padded labels

* Address PR feedback

netbox/users/forms/model_forms.py

@@ -1,6 +1,8 @@
 import json
+from collections import defaultdict
 
 from django import forms
+from django.apps import apps
 from django.conf import settings
 from django.contrib.auth import password_validation
 from django.contrib.postgres.forms import SimpleArrayField
@@ -21,6 +23,7 @@ from utilities.forms.fields import (
     DynamicModelMultipleChoiceField,
     JSONField,
 )
+from utilities.string import title
 from utilities.forms.rendering import FieldSet
 from utilities.forms.widgets import DateTimePicker, SplitMultiSelectWidget
 from utilities.permissions import qs_filter_from_constraints
@@ -283,10 +286,24 @@ class GroupForm(forms.ModelForm):
 
 
 def get_object_types_choices():
-    return [
-        (ot.pk, str(ot))
-        for ot in ObjectType.objects.filter(OBJECTPERMISSION_OBJECT_TYPES).order_by('app_label', 'model')
-    ]
+    """
+    Generate choices for object types grouped by app label using optgroups.
+    Returns nested structure: [(app_label, [(id, model_name), ...]), ...]
+    """
+    app_label_map = {
+        app_config.label: app_config.verbose_name
+        for app_config in apps.get_app_configs()
+    }
+    choices_by_app = defaultdict(list)
+
+    for ot in ObjectType.objects.filter(OBJECTPERMISSION_OBJECT_TYPES).order_by('app_label', 'model'):
+        app_label = app_label_map.get(ot.app_label, ot.app_label)
+
+        model_class = ot.model_class()
+        model_name = model_class._meta.verbose_name if model_class else ot.model
+        choices_by_app[app_label].append((ot.pk, title(model_name)))
+
+    return list(choices_by_app.items())
 
 
 class ObjectPermissionForm(forms.ModelForm):